You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Law of Conservation of Mechanical Energy

The blocks A ...

Question

The blocks A and B shown in fig. Have masses $M_{A} = 5 k g$ and $M_{B} = 4 k g$ . The system is released from rest. The speed of B after A has travelled a distance 1 m along the incline is

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C

If A moves down the incline by 1 m, B shal move up by $\frac{1}{2} m$ .

If the speed of B is v, then the speed of A will be 2v.

From conservation of energy,

Gain in KE = loss in PE

$\frac{1}{2} m_{A} (2 v)^{2} + \frac{1}{2} m_{B} v^{2} = m_{A} g \times \frac{3}{5} - m_{B} g \times \frac{1}{2}$

Solving, we get

$v = \frac{\sqrt{g}}{2 \sqrt{3}}$

Suggest Corrections

Similar questions

The blocks A and B shown in fig. Have masses $M_{A} = 5 k g$ and $M_{B} = 4 k g$ . The system is released from rest. The speed of B after A has travelled a distance 1 m along the incline is

Q. Two blocks

A

and

B

shown in figure have masses

M_{A} = 5 k g; M_{B} = 4 k g

. The system is released from rest. The speed of

B

after

A

has travelled a distance

1 m

along the incline is (do not consider dimensional analysis in the options)

Q. In the arrangement shown in figure,

m_{A} = 4 kg

and

m_{B} = 1 kg

. The system is released from rest and block

B

is found to have a speed of

0.3 m/s

after it has descended through a distance of

1 m

. Find the coefficient of friction between the block and the table. Neglect friction elsewhere. (Take

g = 10 {m/s}^{2}

Q. In the arrangement shown in figure

m_{A} = 4.0 kg

and

m_{B} = 1.0 kg .

The system is released from rest and block

B

is found to have a speed

0.3 m/s

after it has descended through a distance of

1 m

. Find the coefficient of friction between the block

A

and the table. Neglect friction elsewhere. (Take

g = 10 m / s^{2}

)

Q. In the arrangement shown in figure

m_{A} = 4.0 kg

and

m_{B} = 1.0 kg .

The system is released from rest and block

B

is found to have a speed

0.3 m/s

after it has descended through a distance of

1 m

. Find the coefficient of friction between the block

A

and the table. Neglect friction elsewhere. (Take

g = 10 m / s^{2}

)

Join BYJU'S Learning Program

The blocks A and B shown in fig. Have masses MA=5kg and MB=4kg. The system is released from rest. The speed of B after A has travelled a distance 1 m along the incline is

The correct option is C If A moves down the incline by 1 m, B shal move up by 12m. If the speed of B is v, then the speed of A will be 2v. From conservation of energy, Gain in KE = loss in PE 12mA(2v)2+12mBv2=mAg×35−mBg×12 Solving, we get v=√g2√3

The blocks A and B shown in fig. Have masses $M_{A} = 5 k g$ and $M_{B} = 4 k g$ . The system is released from rest. The speed of B after A has travelled a distance 1 m along the incline is