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Question

# The blocks of mass m1=1 kg and m2=2 kg are connected by an ideal spring, rest on a rough horizontal surface. The spring is unstressed. The spring constant of spring is K=2 N/m. The coefficient of friction between blocks and horizontal surface is μ=12. Now the left block is imparted a velocity u towards right as shown. The largest value of u (in m/s) such that the block of mass m2 never moves is (Take g=10 m/s2):

A
10
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B
20
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C
5
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D
2
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Solution

## The correct option is A 10The blocks of mass m1=1 kg For the block of mass m2, not to move, the maximumcompression in the spring xo should be such thatkx0=μm2g....(1)Applying work energy theorem to block of mass m1 we get12m1u2=12kx20+μm1gx0....(2)From equation (1) and (2) we get12m1u2=12μ2m22g2K+μ2m1m2g2Kputting the appropriate value we get u=10m/s.

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