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Question

The blue colour produced on adding H2O2 to acidified K2Cr2O7 is due to the formation of:

A
CrO5
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B
Cr2O3
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C
CrO24
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D
CrO3
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Solution

The correct option is A CrO5
The reaction between H2O2 and acidified K2Cr2O7 can be given as:
K2Cr2O7+H2SO4+4H2O22CrO5+K2SO4+5H20
The blue color produced is due to the presence of CrO5.

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