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Question

The bob of a pendulum is released from a horizontal position A as shown in figure. If the length of the pendulum is 2 m, what is the speed which the bob arrives at the lowermost point B, given that it dissipated 10% of its initial energy against air resistance?
1231135_bd3a908220d94d5d909cdafb0c6d6d60.PNG

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Solution

mass of bon =m length of string l
At B P.E of the bob is 0
AT A P.E of the bob =mgl
When bob reaches the point B 5% of P.E is dissipated agains air resistance and rest 95% is converted to k
12mv2=0.95mgl
v=2×0.95×9.8×2
=37.24
v=6.102m/s

1348569_1231135_ans_ee8a358579b44cd793b7b09558af4da8.PNG

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