wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The bob of a simple pendulum executes simple harmonic motion in water with a period t, while the period of oscillation of the bob is t0 in air. Neglecting frictional force of water and given that the density of the bob is (4/3)×1000kg/m3. What relationship between t and t0 is true?

A
t=t0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
t=t0/2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
t=2t0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
t=4t0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C t=2t0
Let V be the volume of the bob.
Thus mass of the bob M=ρbV=43×1000Vkg
Acceleration due to gravity in air is g.
Effective weight of the bob in water Mg=MgB where buoyant force B=(Vρwater)g
43×1000Vg=43×1000VgV×1000g (as ρwater=1000kg/m3)

43×1000Vg=13×1000Vg
g=g4
Now time period of the bob in air to=2πlg
Time period of the bob in water t=2πlg =2π4lg =2×2πlg
t=2to

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Simple Pendulum
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon