The bob of a simple pendulum is imparted a velocity of 5 metre per second when it is at its mean position. To what maximum vertical height will it rise on reaching at its extreme position if 60% of its energy is lost in overcoming the friction of air? (g = 10 m per second square)

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Solution

At the maximum height say ‘h’ the mechanical energy of the bob is only potential energy, so, PE = mgh

But due to loss of energy in air resistance, only 40% of initial mechanical energy is converted to PE.

So, PE = (40/100)KE

=> mgh = (0.4)(½ m)(52)

=> h = (0.4)(0.5)(25)(1/10) = 0.5 m

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