The bob of simple pendulum having density 40003kg/m3 executes SHM in water with a period ′t′s. If the period of oscillation of bob in air is 10s, find the value of ′t′. (Neglect frictional force of water, take density of water as 1000kg/m3)
A
10
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B
20
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C
30
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D
40
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Solution
The correct option is B20 Given, Period of oscillation of bob in air (T)=10s Density of bob (ρ)=40003kg/m3 Density of water (σ)=1000kg/m3 We know that, Time period of oscillation of bob in water (t)=T√1−σρ t=10√1−30004000 t=20s