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Question

The bob of simple pendulum having density 40003 kg/m3 executes SHM in water with a period t s. If the period of oscillation of bob in air is 10 s, find the value of t.
(Neglect frictional force of water, take density of water as 1000 kg/m3)

A
10
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B
20
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C
30
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D
40
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Solution

The correct option is B 20
Given,
Period of oscillation of bob in air (T)=10 s
Density of bob (ρ)=40003 kg/m3
Density of water (σ)=1000 kg/m3
We know that,
Time period of oscillation of bob in water
(t)=T1σρ
t=10130004000
t=20 s

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