Question

The body temperature of a patient is 5.4${}^o$F above the normal temperature. His body temperature now in 0${}^o$C is

• A. 38${}^o$C
• B. 98${}^o$C
• C. 50${}^o$C
• D. 40${}^o$C

Answer 1

The correct option is D 40${}^o$C

Temperature = 98.6${}^o$F + 5.4${}^o$F = 104.0${}^o$F
$(104-32)\times \frac{5}{9}={40}^{o}C$