Question

The boiling point of a gas is $-80°\mathrm{C}$. This temperature is equivalent to

• A. $-193\mathrm{K}$
• B. $193\mathrm{K}$
• C. $353\mathrm{K}$
• D. $-353\mathrm{K}$

Answer 1

The correct option is B

$193\mathrm{K}$

Explanation for the correct option:

b) $193\mathrm{K}$:

Boiling point: - The temperature at which a liquid changes into a gas or vapour at the atmospheric pressure is called its boiling point.

The relation between celsius and kelvin is: $\mathrm{K}=°\mathrm{C}+273$

$$\begin{gathered} \mathrm{K}=°\mathrm{C}+273 \\ \mathrm{K}=-80°\mathrm{C}+273 \\ \mathrm{K}=193 \end{gathered}$$

Explanation for the incorrect options:

Since $-80°\mathrm{C}$ is equivalent to $193\mathrm{K}$, a) $-193\mathrm{K}$, c) $353\mathrm{K}$, d) $-353\mathrm{K}$ are incorrect.

Hence, option (b) is correct. The temperate equivalent to $-80°\mathrm{C}$ is $193\mathrm{K}$.