The boiling point of a solution containing 0.61 g of benzoic acid in 50 g of carbon disulphide assuming 84% dimerization of the acid, where boiling point and Kb of CS2 being 46.2∘C and 2.3Kkgmol−1 is :
A
46.3444∘C
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B
46.3434∘C
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C
46.3334∘C
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D
46.3344∘C
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Solution
The correct option is C46.3334∘C We have, ΔT=(1000×Kb×w)m×W ΔTN=(1000×2.3×0.61)(122×50)[m.wt.ofC6H5COOH=122]ΔTN=0.23 ΔTexp=ΔTN(1−α+αn)=0.23×{1−0.84+(0.842)}=0.23×(1−0.842)=46.3334∘C(C)