The boiling point of a solution made by dissolving 12.0 g of glucose in 100 g of water is 100.34∘C. Calculate the molecular weight of glucose; Kb for water =0.52∘C/m.
A
183.5gmol−1
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B
283.5gmol−1
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C
383.5gmol−1
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D
73.5gmol−1
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Solution
The correct option is A183.5gmol−1 Using the relation for the molecular weight of a solute from elevation in boiling point, we have MwB=Kb(WBWAΔTb×1000)0.52(12100×0.34×1000)(ΔTb=100.34−100=0.34∘C)⇒MWB=183.5gmol−1