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Liquids in Liquids

The boiling p...

Question

The boiling point of a solution of 5 g sulphur in 100 g $C S_{2}$ is ${0.5}^{o} C$ above pure solvent. If the $K_{b}$ of $C S_{2}$ is 2.56 K/m, then find the atomicity of the sulphur in the solvent.

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Solution

The molality of sulphur is $m = \frac{\frac{5 g}{32 g / m o l}}{100 g \times \frac{1 k g}{1000 g}} = 1.5625 m$
The expression for the elevation in the boiling point is $Δ T_{b} = i \times K_{b} \times m$
Hence, $i = \frac{Δ T_{b}}{K_{b} \times m} = \frac{0.5}{2.56 \times 1.5625} = \frac{1}{8} = \frac{n (o b s e r v e d)}{n (t h e o r e t i c a l)}$ .
Hence, the atomicity of sulphur in $C S_{2}$ solvent is 8.
8 atoms of sulphur associate to form one $S_{8}$ molecule.

$8 S \to S_{8}$

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