Question

The boiling point of $D_{2}O$ is greater than $H_{2}O$. It is because:

• A. $D_{2}O$ has lower $K_w$ value
• B. $D_{2}O$ has a lower dielectric constant
• C. $D_{2}O$ is a associated liquid
• D. the molecular weight of $D_{2}O$ is greater than $H_{2}O$

Answer 1

The correct option is D the molecular weight of $D_{2}O$ is greater than $H_{2}O$

$D_{2}O$ has a somewhat higher boiling point because its molecular weight is about $(16+2+2=20)$ and $H_{2}O$ is about $(16+1+1=18)$.