The boiling points of neon and krypton are $- 245. 9^{\circ} C$ and $- 152. 9^{\circ} C$ respectively. Using these data estimate the boiling point of argon. (report answer as the negative of the closest integer)

- 289^{o} C

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- 299^{o} C

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- 199^{o} C

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- 189^{o} C

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Solution

The correct option is C $- 199^{o} C$
The boiling point of argon can be roughly approximated as the average of the boiling points of neon and krypton.
$\frac{- 245.9^{0} C - 152.9^{0} C}{2} = - 199.4^{0} C$
Hence, the boiling point of argon is approximately $- 199.4^{0} C$ .

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The boiling points of neon and krypton are −245.9∘C and −152.9∘C respectively. Using these data estimate the boiling point of argon. (report answer as the negative of the closest integer)

The correct option is C −199oCThe boiling point of argon can be roughly approximated as the average of the boiling points of neon and krypton.−245.90C−152.90C2=−199.40CHence, the boiling point of argon is approximately −199.40C.

The boiling points of neon and krypton are $- 245. 9^{\circ} C$ and $- 152. 9^{\circ} C$ respectively. Using these data estimate the boiling point of argon. (report answer as the negative of the closest integer)

The correct option is C $- 199^{o} C$
The boiling point of argon can be roughly approximated as the average of the boiling points of neon and krypton.
$\frac{- 245.9^{0} C - 152.9^{0} C}{2} = - 199.4^{0} C$
Hence, the boiling point of argon is approximately $- 199.4^{0} C$ .