The Bombay stock exchange(BSE) sensex/index is given by S = log x and NSE index by N=(logx)2 where x > 1. Find the number of times the two indices cross each other.
1
In simple words, we have to find the values for which N = S
(logx)2−logx=0
log x∗(logx−1)=0
Since log x≠0 as x > 1
Therefore, log x=1⇒x=10
Hence there is only one time when the two indices cross each other.