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Question

The Bombay stock exchange(BSE) sensex/index is given by S = log x and NSE index by N=(logx)2 where x > 1. Find the number of times the two indices cross each other.


A

1

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B

2

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C

3

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D

Cannot be determined

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Solution

The correct option is A

1


In simple words, we have to find the values for which N = S

(logx)2logx=0

log x(logx1)=0

Since log x0 as x > 1

Therefore, log x=1x=10

Hence there is only one time when the two indices cross each other.


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