The bond dissociation energy of H-H, C-C,C-H bonds respectively are 104.2, 83.1 and 98.8kcal/mole . The electronegative of c is?

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Solution

△ = EC−H - √EH−H×EC−C

= 98.8 - [(104.2)×(83.1)]12 = 5.75 kcal.

(XC−H) E.N of C-H bond = 0.218 √△ = 0.218 (5.75)12

= 0.43

XC = 0.43 + XH = 0.43 + 2.1 = 2.53

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Similar questions

The bond dissociation energy of H - H, C - C, and C - H bonds respectively are 104.2, 83.1 and 98.8 kcal/ mole. The electronegativity of C is?

The bond dissociation energy of H - H, C - C, and C - H bonds respectively are 104.2, 83.1 and 98.8 Kcal/ mole. The electro negativity of e is

E_{H - H} = 104.2 k c a l m o l^{- 1}

E_{C - C} = 83.1 k c a l m o l^{- 1}

E_{C - H} = 98.8 k c a l m o l^{- l}

X_{H} = 2.1.

H - H, C - C

C - H

104.2, 83.1

98.8

m o l^{- 1}

C - C, C - H

H - H

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