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Standard XII

Chemistry

Physical Properties of Carbon Family

The bond ener...

Question

The bond energies of $N \equiv N$ , $H - H$ and $N - H$ bonds are $945,$ $436$ and $391$ KJ/mole respectively. The enthalpy of the reaction $N_{2} (g) + 3 H_{2} (g) \to 2 N H_{3} (g)$ is

- 93 K J

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- 102 K J

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93 K J

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102 K J

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Solution

The correct option is A $- 93 K J$
$N_{2} (g) + 3 H_{2} (g) \to 2 N H_{3} (g)$

Enthalpy of reaction $=$ B.E. of reactants - B.E. of products
$= 3 \times (H - H) + (N \equiv N) - 2 \times 3 \times (N - H)$

$= 3 \times (436) + (945) - 6 \times (391)$

$= 1308 + 945 - 2346 = 2253 - 2346$

$= - 93 K J$

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Similar questions

Q. Given the bond energies

N \equiv N

H - H

and

N - H

bonds are 945, 436 and 391 KJ

m o l e^{- 1}

respectively, the enthalpy of the following reaction

N_{2 (g)} + 3 H_{2 (g)} \to 2 N H_{3 (g)}

is:

Given the bond energies $N \equiv N$ , $H - H$ and $N - H$ bonds are $945, 436$ and $391 k J m o l e^{- 1}$ respectively, the enthalpy of the following reaction $N_{2} (g) + 3 H_{2} (g) \to 2 N H_{3} (g)$ is

Q. Given are the bond enthalpies:

ϵ_{N \equiv N} = 945 {kJ mol}^{- 1}, ϵ_{H - H} = 436 {kJ mol}^{- 1}

and

ϵ_{(N - H)} = 391 {kJ mol}^{- 1}

. The enthalpy change of the reaction

N_{2} (g) + 3 H_{2} (g) \to 2 N H_{3} (g)

Q. Calculate the heat of formation of ammonia from the following data:

N_{2} (g) + 3 H_{2} (g) ⟶ 2 {N H}_{3} (g)

The bond energies of

N \equiv N, H - H

and

N - H

bonds are

226, 104

and

93

k c a l

respectively.

Q. Given are the bond enthalpies:

ϵ_{N \equiv N} = 945 {kJ mol}^{- 1}, ϵ_{H - H} = 436 {kJ mol}^{- 1}

and

ϵ_{(N - H)} = 391 {kJ mol}^{- 1}

. The enthalpy change of the reaction

N_{2} (g) + 3 H_{2} (g) \to 2 N H_{3} (g)

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The bond energies of N≡N, H−H and N−H bonds are 945, 436 and 391 KJ/mole respectively. The enthalpy of the reaction N2(g)+3H2(g)→2NH3(g) is

The correct option is A −93KJN2(g)+3H2(g)→2NH3(g)Enthalpy of reaction = B.E. of reactants - B.E. of products=3×(H−H)+(N≡N)−2×3×(N−H)=3×(436)+(945)−6×(391)=1308+945−2346=2253−2346=−93KJ

The bond energies of $N \equiv N$ , $H - H$ and $N - H$ bonds are $945,$ $436$ and $391$ KJ/mole respectively. The enthalpy of the reaction $N_{2} (g) + 3 H_{2} (g) \to 2 N H_{3} (g)$ is