The bond energy order of $H e^{2 +}$ and $H e H^{+}$ is:

H e^{2 +} > H e H^{+}

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H e H^{+} = H e^{2 +}

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H e H^{+} > H e^{2 +}

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None of the above

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Solution

The correct option is D $H e H^{+} > H e^{2 +}$
The bond energy order of $H e^{2 +}$ is $\frac{(2 - 2)}{2} = 0$ and $H e H^{+}$ is $\frac{3 - 1}{2} = 1$ .

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