The bond length order in following compound is:

x > y > z > w

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

z > y > x > w

No worries! We‘ve got your back. Try BYJU‘S free classes today!

y > z > x > w

No worries! We‘ve got your back. Try BYJU‘S free classes today!

z > x > y > w

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $x > y > z > w$
Since double bond has $σ$ as well as n-bond so it is more stronger than $σ$ bond (single bond).
Bond order = $w > z > y > x$
Bond length $α$ $\frac{1}{b o n d o r d e r}$ = $w < z < y < x$
i.e. exo bonds are lengthier than endo due to flexibility.

Suggest Corrections

Similar questions

w < x < z

w < y < z

w < z

x < y

y < z

C H_{3} - C H_{2} - C H_{2} - C H_{2} - C H_{3}

C H_{3} - C H_{3} | C H - C H_{2} - C H_{3}

C H_{3} - C H_{3} | C | C H_{3} - H

C H_{3} - C H_{3}

Join BYJU'S Learning Program