Question

The bond length order in following compound is:

• A. $x>y>z>w$
• B. $z>y>x>w$
• C. $y>z>x>w$
• D. $z>x>y>w$

Answer 1

The correct option is A $x>y>z>w$

Since double bond has $\sigma$ as well as n-bond so it is more stronger than $\sigma$ bond (single bond).

Bond order = $w>z>y>x$

Bond length $\alpha$$\frac{1}{bondorder}$ = $w<z<y<x$

i.e. exo bonds are lengthier than endo due to flexibility.