Question

The bond order in $N_2^{+}$ ion is

[Pb. CET 2004]

• A. 1
• B. 2
• C. 2.5
• D. 3

Answer 1

The correct option is C 2.5

$B.O.=\frac{No.of{N}_b-No.of{N}_a}{2}=\frac{5}{2}=\mathrm{2.5.}$