The bond order of a molecule is given by:

the difference between the number of electrons in bonding and antibonding orbitals

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total number of electrons in bonding and antibonding orbitals

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twice the difference between the number of electrons in bonding and antibonding orbitals

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half the difference number of electrons in bonding and antibonding orbitals

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Solution

The correct option is A total number of electrons in bonding and antibonding orbitals
Bond order is given by half of the difference between the no. of electrons in the bonding orbital and no. of electrons in the antibonding orbital.
$B o n d O r d e r = \frac{N o . o f e^{-} i n b o n d i n g o r b i t a l - N o . o f e^{-} i n a n t i b o n d i n g o r b i t a l}{2}$

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