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Bond Order and Enthalpy

The bond orde...

Question

The bond order of ${H_{2}}^{-}$ ion is $\frac{1}{2}$ . If it has 2 bonding electrons, calculate the number of antibonding electrons.

A

4

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B

3

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C

2

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D

1

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Solution

The correct option is C 1
Bond order $= \frac{1}{2} (N_{b} - N_{a})$

$= \frac{1}{2} = \frac{1}{2} (2 - N_{a})$

$∴ N_{a} = 2 - 1 = 1$

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