The bond order of NO molecule is

[MP PET 1996]

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2.5

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Solution

The correct option is C 2.5
$B . O . = \frac{N o . o f b o n d i n g e^{-} - N o . o f a n t i b o n d i n g e^{-}}{2}$
$= \frac{8 - 3}{2} = \frac{5}{2} = 2.5$

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