Question

The bond order of $O_2^{+}$ is

• A. $1$
• B. $1.5$
• C. $2.5$
• D. $3$

Answer 1

The correct option is C $2.5$

The electronic configuration of $O_2^{+}$ according to MOT is $\left({\sigma }_{1s}{)}^2\right({\sigma }_{1s}^{\ast }{)}^2\left({\sigma }_{2s}{)}^2\right({\sigma }_{2s}^{\ast }{)}^2\left({\sigma }_{2p_z}{)}^2\right({\pi }_{2p_x}{)}^2=\left({\pi }_{2p_y}{)}^2\right({\pi }_{2p_x}^{\ast }{)}^1=\left({\pi }_{2p_y}^{\ast }{)}^0\right({\sigma }_{2p_z}^{\ast }{)}^0$
Bond order is $=\frac{10-5}{2}=2.5$