Question

The bond order of superoxide ion is –

• A. 0.5
• B. 1.5
• C. 2.5
• D. 3.5

Answer 1

The correct option is B 1.5

As per MOI, $O_2\ominus$ :
$\begin{array}{cc}\upharpoonleft \downharpoonright & \upharpoonleft \end{array}$
${\pi }^{\star }2px{\pi }^{\star }2py$

$Bondorder=\frac{1}{2}[N_b-N_a]$

$\frac{1}{2}[10-7]=1.5$