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Question

The boolean expression for the output 'F' of the logic circuit shown in the figure below is


A
¯¯¯¯¯XY+¯¯¯¯¯X.¯¯¯¯Y+¯¯¯¯Z
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B
¯¯¯¯¯XY+X¯¯¯¯Y+Z
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C
XY+¯¯¯¯¯X.¯¯¯¯Y+¯¯¯¯Z
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D
¯¯¯¯¯XY+X¯¯¯¯Y+¯¯¯¯Z
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Solution

The correct option is D ¯¯¯¯¯XY+X¯¯¯¯Y+¯¯¯¯Z
F=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(XY)Z=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(XY+¯¯¯¯¯X.¯¯¯¯Y)Z

F=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(XY+¯¯¯¯¯X.¯¯¯¯Y)+¯¯¯¯Z=¯¯¯¯¯¯¯¯¯¯¯¯¯(XY)(¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯X.¯¯¯¯Y)+¯¯¯¯Z

F=(¯¯¯¯¯X+¯¯¯¯Y)(X+Y)+¯¯¯¯Z=¯¯¯¯¯XY+X¯¯¯¯Y+¯¯¯¯Z

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