The Boolean expression p - q - r - q - p is equivalent to

Given: nbsp;(p ∧ q) ⇒ ((r ∧ q) ∧ p) =∼(p ∧ q)∨ ((r ∧ q) ∧ p) =∼(p ∧ q)∨((r ∧ q) ∧ (p∧ q)) =[∼(p ∧ q)∨(p∧ q)]∧[∼(p ∧ q)∨(r ∧ q)] =∼(p ∧ q)∨(r ∧ q) =(p ∧ q) ⇒(r ...

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Byju's Answer

Standard XII

Mathematics

Direct Method of Validation

The Boolean e...

Question

The Boolean expression $(p \land q) \Rightarrow ((r \land q) \land p)$ is equivalent to

(p \land q) \Rightarrow (r \land q)

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(q \land r) \Rightarrow (p \land q)

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(p \land r) \Rightarrow (p \land q)

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(p \land q) \Rightarrow (r \lor q)

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Solution

The correct option is A $(p \land q) \Rightarrow (r \land q)$

This is equivalent to $(p \land q) \Rightarrow (r \land q)$

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Similar questions

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((p \land q) \lor (p \lor \sim q)) \land (\sim p \land \sim q)

is equivalent to :

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(p \land \sim q) \lor q \lor (\sim p \land q)

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Q. The Boolean expression

(p \land \sim q) \Rightarrow (q \lor \sim p)

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Q. The Boolean expression

\sim (p \Rightarrow (\sim q))

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Q. The Boolean expression

\sim (p \lor q) \lor (\sim p \land q)

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The Boolean expression (p∧q)⇒((r∧q)∧p) is equivalent to

The correct option is A (p∧q)⇒(r∧q) This is equivalent to (p∧q)⇒(r∧q)

The Boolean expression $(p \land q) \Rightarrow ((r \land q) \land p)$ is equivalent to

The correct option is A $(p \land q) \Rightarrow (r \land q)$

This is equivalent to $(p \land q) \Rightarrow (r \land q)$