Question

The Boolean function F(X,Y) realized by the given circuit is

• A. $\overline{X}Y+X\overline{Y}$
• B. $\overline{X}.\overline{Y}+XY$
• C. $\overline{X}+Y$
• D. $\overline{X}.\overline{Y}$

Answer 1

The correct option is A $\overline{X}Y+X\overline{Y}$

The given circuit is the standard circuit. It is the implementation of EX-OR gate using NAND gates.
Hence, $F=X\oplus Y=\overline{X}Y+X\overline{Y}$