The Boolean function F(X,Y) realized by the given circuit is
A
¯¯¯¯¯X.¯¯¯¯Y
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B
¯¯¯¯¯X+Y
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C
¯¯¯¯¯XY+X¯¯¯¯Y
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D
¯¯¯¯¯X.¯¯¯¯Y+XY
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Solution
The correct option is C¯¯¯¯¯XY+X¯¯¯¯Y The given circuit is the standard circuit. It is the implementation of EX-OR gate using NAND gates.
Hence, F=X⊕Y=¯¯¯¯¯XY+X¯¯¯¯Y