The Born Haber cycle below represents the energy changes occurring at 298K when KH is formed from its elementsv - - H atomisation K - 90 kJ-molw - - H ionisation K - 418 kJ-molx - - H dissociation H - 436 kJ-moly - - H electron affinity H - 78 kJ-molz - - H lattice KH - 710 kJ-molIn terms of the letters v to z the expression for - H electron affinity of H is - H electron affinity is -I

The correct option is D y The electron affinity Δ H _ electron affinity #160;of an atom or molecule is defined as the amount of energy #160;r ...

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Standard XII

Chemistry

Physical Properties of Boron Family

The Born Habe...

Question

The Born Haber cycle below represents the energy changes occurring at 298K when KH is formed from its elements
v : ${Δ H}_{a t o m i s a t i o n}$ K = 90 kJ/mol
w : ${Δ H}_{i o n i s a t i o n}$ K = 418 kJ/mol
x : ${Δ H}_{d i s s o c i a t i o n}$ H = 436 kJ/mol
y : ${Δ H}_{e l e c t r o n a f f i n i t y}$ H = 78 kJ/mol
z : ${Δ H}_{l a t t i c e}$ KH = 710 kJ/mol
In terms of the letters v to z the expression for
${Δ H}_{e l e c t r o n a f f i n i t y}$ of H is ${Δ H}_{e l e c t r o n a f f i n i t y}$ is __.
I

y

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Solution

The correct option is D $y$
The electron affinity $Δ H_{e l e c t r o n a f f i n i t y}$ of an atom or molecule is defined as the amount of energy released when an electron is added to a neutral atom or molecule in the gaseous state to form a negative ion. It is exothermic as heat energy is released from the system.

$Δ H_{e l e c t r o n a f f i n i t y}$ should be y not y/2.

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Similar questions

Q. The Born Haber cycle below represents the energy changes occurring at 298K when KH is formed from its elements
v :

{Δ H}_{a t o m i s a t i o n}

K = 90 kJ/mol
w :

{Δ H}_{i o n i s a t i o n}

K = 418 kJ/mol
x :

{Δ H}_{d i s s o c i a t i o n}

H = 436 kJ/mol
y :

{Δ H}_{e l e c t r o n a f f i n i t y}

H = 78 kJ/mol
z :

{Δ H}_{l a t t i c e}

KH = 710 kJ/mol

Out of v to y the most exothermic is___.

The Born Haber cycle below represents the energy changes occurring at 298K when KH is formed from its elements :
v :

{Δ H}_{a t o m i s a t i o n}

K = 90 kJ/mol
w :

{Δ H}_{i o n i s a t i o n}

K = 418 kJ/mol
x :

{Δ H}_{d i s s o c i a t i o n}

H = 436 kJ/mol
y :

{Δ H}_{e l e c t r o n a f f i n i t y}

H = 78 kJ/mol
z :

{Δ H}_{l a t t i c e}

KH = 710 kJ/mol

In terms of the letters v to z the expression for
(i)

Δ

H for the reaction

2 K

(s) +

H_{2}

(g)

⟶

2 K H

(s).
will be

Δ

$H =_____?

Q. The Born Haber cycle below represents the energy changes occurring at 298K when

K H

is formed from its elements
v :

{Δ H}_{a t o m i s a t i o n}

K = 90 k J / m o l

w :

{Δ H}_{i o n i s a t i o n}

K = 418 k J / m o l

x :

{Δ H}_{d i s s o c i a t i o n}

H = 436 k J / m o l

y :

{Δ H}_{e l e c t r o n a f f i n i t y}

H = 78 k J / m o l

z :

{Δ H}_{l a t t i c e}

K H = 710 k J / m o l

Out of v to y the most endothermic is___.

Q. The Born Haber cycle below represents the energy changes occurring at 298K when

K H

is formed from its elements
v :

{Δ H}_{a t o m i s a t i o n}

K = 90 k J / m o l

w :

{Δ H}_{i o n i s a t i o n}

K = 418 k J / m o l

x :

{Δ H}_{d i s s o c i a t i o n}

H = 436 k J / m o l

y :

{Δ H}_{e l e c t r o n a f f i n i t y}

H = 78 k J / m o l

z :

{Δ H}_{l a t t i c e}

K H = 710 k J / m o l

Calculate the value of

Δ

H

showing all your working.

The Born Haber cycle below represents the energy changes occurring at 298K when

K H

is formed from its elements
v :

{Δ H}_{a t o m i s a t i o n}

K = 90 k J / m o l

w :

{Δ H}_{i o n i s a t i o n}

K = 418 k J / m o l

x :

{Δ H}_{d i s s o c i a t i o n}

H = 436 k J / m o l

y :

{Δ H}_{e l e c t r o n a f f i n i t y}

H = 78 k J / m o l

z :

{Δ H}_{l a t t i c e}

K H = 710 k J / m o l

On complete reaction with water,

0.1 g

K H

gave a solution requiring 25

{c m}^{3}

of 0.1M

H C l

for neutralisation.Calculate the relative atomic mass of potassium from this information.

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