wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The box 1 contains chips numbered 3, 6, 9, 12 and 15. The box 2 contains chips numbered 11, 6, 16, 21 and 26. Two chips, one from each box are drawn at random.

The number written on these chips are multiplied. The probability for the product to be an even number is

A
625
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
25
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
35
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1925
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 1925

Product will be even only when (either both even) or (1st even, 2nd odd) or (IInd even, Ist odd)

So Req. prob. = P(even & even) + P(even & odd) + P(odd & even)

=(23×35)+(25×25)+(35×35)=1925

flag
Suggest Corrections
thumbs-up
7
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Conditional Probability
ENGINEERING MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon