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Question

The box with a square base is to have an open top. The area of the material for making the box is 192 sq.cm. What should be its dimensions in order that the volume is as large as possible?

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Solution

LetthedensionsofthebaseoftheopenboxbexcmandxcmandheightbeycmTheareaofthematerialoftheopenbox(Areaofthebase)+4(areaofverticalface)192=(x×x)+4(xy)192=x2+4xy192x24x=yLetvbethevolumeofthebox,V=basearea×height=x2y=x2(192x24x)V=x(192x24)=192xx34dvdx=1923×x24dvdx=0x2=64since,xislengthoftheside,itcannotbe0vex8and,d2vdx2=32x(d2vdx2)x=8=32(8)V=ismaximumwhenx=8cmwhenx=8,theny=192824(8)=4cmDimensionsare8cm&4cmlestpossiblevolumeofbox(cube)V=x2y=(8)2(4)=256sqcm

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