The boys and girls are in the ratio $8 : 3$ ,. If the number of girls are $40$ . How many boys are there in the school?

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Solution

$\frac{b o y}{g i r l} = \frac{8}{3}$

No. of girls $= 40$ .

$\Rightarrow \frac{b o y}{40} = \frac{8}{3}$

$\Rightarrow$ No. of boys $= \frac{40 \times 8}{3} \approx 106$

$∴$ No. of boys $= 106$ .

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The boys and girls are in the ratio 8:3,. If the number of girls are 40. How many boys are there in the school?

boygirl=83No. of girls =40.⇒boy40=83⇒ No. of boys =40×83≈106∴ No. of boys =106.

The boys and girls are in the ratio $8 : 3$ ,. If the number of girls are $40$ . How many boys are there in the school?

$\frac{b o y}{g i r l} = \frac{8}{3}$

No. of girls $= 40$ .

$\Rightarrow \frac{b o y}{40} = \frac{8}{3}$

$\Rightarrow$ No. of boys $= \frac{40 \times 8}{3} \approx 106$

$∴$ No. of boys $= 106$ .