Question

The breakdown field strength for dry air is $3\times {10}^6$ V/m . Each of the plates of parallel plate capacitor has an area of $0.2m^2$. The maximum charge that can be collected is:

• A. $5.3\mu$ C
• B. $0.6\mu$ C
• C. $1.5\mu$ C
• D. $4.56\mu$ C

Answer 1

The correct option is A $5.3\mu$ C

We know electric field between capacitors $=\frac{Q}{{\epsilon }_{0}A}$
$\therefore$ maximum charge is.
$\frac{Q}{A{\epsilon }_0}=3\times {10}^6$
$Q=(3\times {10}^6)\times (0\cdot 2)\times (8\cdot 825\times {10}^{-12})$
$Q=5\cdot 295\times {10}^{-6}C$