The breaking stress of a material is 108N/m, density of material is 3000kg/m3
. Find the greatest
length of wire that could hang vertically without breaking. (Pause the video and solve without
looking at the solution).

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Solution

Breaking stress = σ = 10^8 n/m^2

density of material = ρ = 3000 kg/m^3
g=10m/s²
let the maximum length that can be hung vertically be L
Let cross sec area = A
volume of wire=AL
mass of wire=ρAL
when hung force acting on the wire
F=ρALg
F/A=ρlg
σ= ρlg
now maximum, stress that wire can withstand σ=σb
so,

ρLg = σb = 10^8 n/m^2

L = 10^8 / ρg

= 10^8 / 3000*10
= 3333.33 m

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