Question

The Brewster's angle $i_b$ for an interface dividing mediums of refractive index $\mu =1$ and $\mu =\sqrt{3}$ should be

$($Light is incident from rarer to denser medium$)$

• A. ${15}^{\circ }$
• B. ${45}^{\circ }$
• C. ${30}^{\circ }$
• D. ${60}^{\circ }$

Answer 1

The correct option is D ${60}^{\circ }$

As per Brewster's law,

$\tan i_b=\mu$

or, $\tan i_b=\sqrt{3}$

$\Rightarrow i_b={60}^{\circ }$