Question

The brown ring complex compound is formulated as $\left[Fe{\left(H_{2}O\right)}_{5}NO\right]{SO}_4$. The oxidation state of iron is

• A. 0
• B. 1
• C. 2
• D. 3

Answer 1

Answer: (B)

1

$\left[Fe\right(H_{2}O{)}_{5}NO]S{O}_4$ is a brown ring complex.In this complex NO is present in +1 oxidation state .Now calculating oxidation state of iron by balancing the overall charge.

Let the oxidation state of iron be x.

x + 0 +1 -2 =0 i.e. x=1

Oxidation state of iron is +1.

Hence, correct option is (B)