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VBT Tetrahedral vs Square Planar

The 'brown ri...

Question

The 'brown ring' formed at the junction of two layers in the test of nitrate is due to the formation of a complex ion, $[F e (H_{2} O)_{5} N O]^{2 +}$ . Which of the following statements are correct for this complex. $[μ = 3.87 B . M .]$ ?

O x i d a t i o n s t a t e o f F e i s + 1 a n d N O e x i s t s a s N O^{+}

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T h e c o m p l e x i o n i s i n o c t a h e d r a l g e o m e t r y a s a t t a i n e d b y s p^{3} d^{2} h y b r i d i z a t i o n .

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The complex is paramagnetic and has three unpaired electrons \: due to transfer of electron from NO to

F e^{2 +} .

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T h e c o m p l e x i s i n o c t a h e d r a l g e o m e t r y a s a t t a i n e d b y d^{2} s p^{3} h y b r i d i z a t i o n .

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Solution

The correct options are
A $O x i d a t i o n s t a t e o f F e i s + 1 a n d N O e x i s t s a s N O^{+}$
B $T h e c o m p l e x i o n i s i n o c t a h e d r a l g e o m e t r y a s a t t a i n e d b y s p^{3} d^{2} h y b r i d i z a t i o n .$
C The complex is paramagnetic and has three unpaired electrons \: due to transfer of electron from NO to $F e^{2 +} .$
$N u m b e r o f u n p a i r e d e l e c t r o n s = 3; S o, μ = \sqrt{3 (2 + 3)} = 3.87 B . M .$

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Similar questions

[F e (H_{2} O)_{5} N O]^{2 +}

N O_{3}^{-}

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