The correct option is D CaCl2(aq)
The bulb will glow only when there are mobile ions and the circuit is complete.
Ionic compounds like KOH and CaCl2(aq) dissociate in water to furnish ions. Thus, the bulb glows in the presence of KOH(aq) or CaCl2(aq)
KOH(aq)→K+(aq)+OH−(aq)
CaCl2(aq)→Ca2+(aq)+2OH−(aq)
C6H12O6(s) and C2H5OH(l) do not furnish any ions. Thus, the bulb does not glow.