Question

The bulk modulus and the density of water are greater than those of air. With this much of information, we can say that velocity of sound in air
(a) is larger than its value in water
(b) is smaller than its value in water
(c) is equal to its value in water
(d) cannot be compared with its value in water.

Answer 1

(d) cannot be compared with its value in water.

If B is the bulk modulus and ρ is the density, then the velocity of sound is given by:
$\mathrm{Velocity}=\sqrt{\frac{B}{\mathrm{\rho }}}$
If both B and ρ are greater, then we cannot compare $\frac{2B}{2\mathrm{\rho }}=\frac{3B}{3\mathrm{\rho }}=\frac{B}{\mathrm{\rho }}$.
For proper comparison, we need numerical values.