The bulk modulus of a liquid of density 8000 kgm-3 is 2- 109 Nm-2- The speed of sound in that liquid is in ms-1

The correct option is C 500Bulk modulus of liquid #160; B = 2× 10^9 #160; N/m^2 Density #160; ρ = 8000 #160; #160; kg/m^3 So, speed of so ...

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Standard XII

Physics

Poisson's Effect

The bulk modu...

Question

The bulk modulus of a liquid of density $8000 k g m^{- 3}$ is $2 \times 10^{9} N m^{- 2}$ . The speed of sound in that liquid is (in $m s^{- 1}$ )

200

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250

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100

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350

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500

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Solution

The correct option is C 500
Bulk modulus of liquid $B = 2 \times 10^{9} N / m^{2}$
Density $ρ = 8000 k g / m^{3}$
So, speed of sound $v = \sqrt{\frac{B}{ρ}}$
$∴$ $v = \sqrt{\frac{2 \times 10^{9}}{8000}} = 500 m / s$

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The bulk modulus of a liquid of density 8000kgm−3 is 2×109Nm−2. The speed of sound in that liquid is (in ms−1)

The correct option is C 500Bulk modulus of liquid B=2×109 N/m2Density ρ=8000 kg/m3So, speed of sound v=√Bρ∴ v=√2×1098000=500 m/s

The bulk modulus of a liquid of density $8000 k g m^{- 3}$ is $2 \times 10^{9} N m^{- 2}$ . The speed of sound in that liquid is (in $m s^{- 1}$ )

The correct option is C 500
Bulk modulus of liquid $B = 2 \times 10^{9} N / m^{2}$
Density $ρ = 8000 k g / m^{3}$
So, speed of sound $v = \sqrt{\frac{B}{ρ}}$
$∴$ $v = \sqrt{\frac{2 \times 10^{9}}{8000}} = 500 m / s$