The Cahn-Ingold-Prelog (CIP) priorities of the groups and the absolute configuration (R/S) of the following compound are:

C H_{2} O H > C H (C H_{3})_{2} > C H = C H_{2} > C H_{3} a n d S

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C H_{2} O H > C H = C H_{2} > C H (C H_{3})_{2} > C H_{3} a n d S

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C H_{2} O H > C H = C H_{2} > C H (C H_{3})_{2} > C H_{3} a n d R

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C H_{2} O H > C H (C H_{3})_{2} > C H = C H_{2} > C H_{3} a n d R

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Solution

The correct option is B $C H_{2} O H > C H = C H_{2} > C H (C H_{3})_{2} > C H_{3} a n d S$
According to CIP rule the priorities of the groups are
$C H_{2} O H > C H = C H_{2} > C H (C H_{3})_{2} > C H_{3}$

Here the counting of substituents from $1$ to $3$ is anticlockwise keeping the lowest priority group below the plane. So, the absolute configuration of the given compound is ‘ $S$ ’.

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According to cahn-Ingold-prelog sequence rules, the correct order of priority of the given groups is

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