The calculated mass of 20Ca40 is 40.328u. It releases 306.3 MeV energy in a nuclear process. Its isotopic mass is.
A
39.998
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B
40.6570
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C
0.3290
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D
2.85×104
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Solution
The correct option is B39.998 BE=Δm×931MeV 306.3=Δm×931 Δm=0.3290 Δm= calculated mass − isotonic mass −Isotonic mass =\Delta m− calculated mass =0.3290−40.328 =−39.998 ∴ Isotopic mass =39.998