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Question

The calculated spin only magnetic moment of Cr2+ ion is :

A
5.92 BM
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B
2.84 BM
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C
3.87 BM
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D
4.90 BM
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Solution

The correct option is D 4.90 BM
Cr2+1s22s22p63s23p63d4
n(number of unpaired electrons)=4μ=n(n+2)
=(4(4+2)
=4.8989
=4.9B.M

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