Question

The calculated spin only magnetic moment of $C{r}^{2+}$ is :

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Answer 1

Electronic configuration
$C{r}^{2+}:\left[Ar\right]3d^4$
No. of unpaired electron = 4
$\mu =\sqrt{n(n+2)}BM$
$\mu =\sqrt{4(4+2)}BM$
$\mu \approx 4.90BM$