Question

The calculated value of magnetic moment of ${}_{23}{V}^{3+}$ is :

• A. $1.73{\mu }_B$
• B. $2.83{\mu }_B$
• C. $3.87{\mu }_B$
• D. $4.90{\mu }_B$

Answer 1

The correct option is B $2.83{\mu }_B$

Consider the electronic configuration of ${}_{23}{V}^{3+}$ is $\left[Ar\right]3d^2$.
Hence the number of unpaired electrons is 2.
The dipole moment is given by $\sqrt{n(n+2)}$ where n is the number of unpaired electrons.
$D.M$ = $\sqrt{2(n+2)}$
= $\sqrt{6}$
=$2.83{\mu }_B$
Hence option B is the right answer.