The correct option is C decrease it by 1.0%
We know that, frequency of oscillations of charge in the LC circuit is,
f=12π√LC
Given, f= constant.
⇒LC= constant
After differentiating, we get,
L dC+C dL=0
⇒dLL=−dCC
⇒dLL×100=−dCC×100
So, percentage change in inductance and that in capacitance are of same magnitude.
Negative sign indicates that, the nature of the change in them will be opposite.
As the capacitance is increased, the inductance should be decreased.
Therefore, the inductance should be decreased by 1.0%.
Hence, option (C) is the correct answer.