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Question

The capacitance of a condenser is 20μF and it is charged to a potential of 2000 V. The energy stored in it will be :

A
zero
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B
40 J
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C
80 J
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D
120 J
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Solution

The correct option is C 40 J
Given
C=20μF,V=2000V
Energy stored in the condenser is U=12CV2=12×20×106×(2000)2=40J

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