Question

The capacitance of a conductor is 2 pF and its potential is 100 V. When it is connected to an uncharged conductor, the potential becomes 8 V. What is the capacitance of the second conductor? What are the charges on them?

Answer 1

Dear student
$$\begin{gathered} commonpotential \\ V=\frac{C_1{V}_1+C_2{V}_2}{C_1+C_2} \\ 8=\frac{200}{2+C_2} \\ {C}_2=23pF \\ {q}_1=8\times 2\times {10}^{-12}=16\times {10}^{-12} \\ {q}_2=23\times 8=184\times {10}^{-12} \\ Regards \end{gathered}$$